3 answers

Which of the following procedures islare correct when you crystallize a solid compound? (Select all that apply)1) Once a solution

Question:

Which of the following procedures islare correct when you crystallize a solid compound? (Select all that apply) 1) Once a solution is formed, cool it down in ice rapidly to ensure no contaminants can be entrapped in the crystals 2) Using a solvent that does not dissolve the solid at room temperature 3) Using as much solvent as possible to quickly make a true solution Ensuring the solution to look slightly hazy at boiling temperature 5) Using a solvent that dissolves the solid at boiling temperature 6) Heating up the flask containing solid fast before introducing solvent


Answers

Select the correct statement (a) an organic liquid vaporizes at a temperature below its boiling point in steam distillation. (b) Lassaigne's test for the detection of sulphur fails if organic compound is volatile. (c) naphthalene can be separated from ammonium chloride by sublimation method. (d) $\mathrm{CC} 1_{4}$ does not give a white precipitate with silver nitrate solution.

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The lower the steps involved in the formation of us A solution described in the problem. First, we're gonna break out the individual, solve it or the Salyut components. Anytime we break up, the forces associate ID with anything attracted to each other. This requires energy. So this is going to be endo thermic.

Then the second step is going to break up the interactions associated with the solvent molecules in order to make room for the Salyut here again to break up that attractive force that already exists between the solvent molecules that's going to require energy. So this is also Endo thermic and then last of all, we're going to form the solution by having the Salyut in the solvent interactions occur. If we are allowing interactions to occur that want to occur than energy will be released and this will be exo thermic. So the first step is end author make The second step is endo thermic both of these being endo thermic And then the last step, when we allow things to naturally occur, will be exo thermic. So the answer that is going to be de endo thermic endo, thermic, exo, thermic.

However, according to the all, given a statement in this problem, we can say that solution has more molecule er randomness than if you're solvent has. So the entropy change between solution and solid is larger than entropy change between pure solvent and solid. I can also write the value of still have as solution is greater than they have as solving so. According to the option here, only option each correct answer. Only option it direct answer Among all the given options in this problem, I hope you understand the solution of this problem..

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