1 answer

The hydrocarbon which can react with sodium in liquid ammonia is (a) $\mathrm{CH}_{3} \mathrm{CH}_{2} \mathrm{CH}_{2} \mathrm{C}=\mathrm{CCH}_{2} \mathrm{CH}_{2} \mathrm{CH}_{3}$ (b) $\mathrm{CH}_{3}

Question:

The hydrocarbon which can react with sodium in liquid ammonia is (a) $\mathrm{CH}_{3} \mathrm{CH}_{2} \mathrm{CH}_{2} \mathrm{C}=\mathrm{CCH}_{2} \mathrm{CH}_{2} \mathrm{CH}_{3}$ (b) $\mathrm{CH}_{3} \mathrm{CH}_{2} \mathrm{C} \equiv \mathrm{CH}$ (c) $\mathrm{CH}_{3} \mathrm{CH}=\mathrm{CHCH}_{3}$ (d) $\mathrm{CH}_{3} \mathrm{CH}_{2} \mathrm{C} \equiv \mathrm{CCH}_{2} \mathrm{CH}_{3}$


Answers

The hydrocarbon which can react with sodium in liquid ammonia is (a) $\mathrm{CH}_{3} \mathrm{CH}_{2} \mathrm{CH}_{2} \mathrm{C}=\mathrm{CCH}_{2} \mathrm{CH}_{2} \mathrm{CH}_{3}$ (b) $\mathrm{CH}_{3} \mathrm{CH}_{2} \mathrm{C} \equiv \mathrm{CH}$ (c) $\mathrm{CH}_{3} \mathrm{CH}=\mathrm{CHCH}_{3}$ (d) $\mathrm{CH}_{3} \mathrm{CH}_{2} \mathrm{C} \equiv \mathrm{CCH}_{2} \mathrm{CH}_{3}$

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