5 answers

In the Venn diagram contains set of Odd number (0) and the set of rultiples of 3 () Use the

Question:

In the Venn diagram contains set of Odd number (0) and the set of rultiples of 3 () Use the information Elen t0 answer the questions below_ List the clements of the following OuM = 6, 12 3,9, IL OoM= M' The uuversal set D = n(0) = D n(M')-noom) = @) n(ofM) = b) M/o =


Answers

Using the Venn diagram in Figure 2.21 find each set.
$$
A-(B-C)
$$

.

In this problem, let us first define what is over in diagram. Over in diagram is of pictorial representation to illustrate the relationship between different sets. No, Let us look at Part one, which is I. As a proper subset of B. So this is subset B.

This is the set B. And this is sad, right? This is the main suspect. S. You see that all the elements of I within the elements of B and I is not equal to. Next look at in the the stormed sets, which means that intersection B.

S. Fine, Which means that two sets do not have any intersection. This is A me and this is needless. Listen, look at my toe which is A. And B aren't not destroyed, which means that not this joint, which means that intersection B is some set, correct.

The money is this? So you can see here that intersection B. Which is this has some what? That's all..

For any three events A, B and C. The probability off A or B or C is defined as P off a plus. PFT plus PFC minus P off A and B minus. P off A and C and miners, P, O, B and C plus P, off A and B and C. In this question p off a is 0.38 plus p off.

Be at that 0.26 plus PFC when. 14 minus p off A and B 0.12 minus p off A and C 0.3 minus p off B and C 0.9 and the add P off A and B and C at 0.1 Calculate thes we got P off A or B or C is 0.55..

Yeah, so the probability of B given C equals zero tells us that if we are in B. Yeah, then C is nowhere near. Alright. Could be somewhere near it, but it's definitely not overlapping now, the probability of a given C is one would mean that, and if we are in C then we must be in A. So A is going to be the larger circle like this.

Yeah, this would mean that the probability of a given C is one. So if she happens, then he has to happen as well..

Given number of elemental air, they couldn't read it and be to a number of filaments and a union be Is it better? Did you do? Yeah. Okay. Yeah. Are you afraid of engine complement of faith? As 19. You're here.

You have to draw when died. Room? Yeah. Mhm. Okay, now here. Let this be.

We have this baby. It is Secretary B. Now, given your first, we'll find number of elements in a intersection. Be that is equal to number of filling means me. There's a number of filaments in blue minus number of elements in Amy B.

As you know, all these values, you can just substitute 28 plus 12 minus 32 that is equal to eight. Therefore, a intersection be will be eat And now a number of filaments in compliment off here intersection be that ISS This part sequence too. Number of elemental B minus No offering. Eating a intersection be that is going to be 12 minus Meet it is going to be full. So here in school similarly, more fundamental.

A intersection Compliment off B that iss this part Zach Quinto loaf elements in a minus number of elements. Um Hey, intersection. We That would be number of remains in a has given us 28 minus eight. That has been debate 20. So this is equal to 20.

No, we have to find I didn't go fell. Amazing you. Why so given number of elements in complement of faith, it was 19. That is the entire radio apart. To me, that is equal to 19.

So we'll get number of elements and you will be able to 19 minus number of elements in a compliment intersection be you compliment intersection Mhm that is equal to 19 minus four. That is 50. So here, whose area? It's going to be 15 elements..

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