5 answers

Each battery has an emf of 1.3 volts_ The length of the tungsten filament in each bulb is 0.011 m_

Question:

Each battery has an emf of 1.3 volts_ The length of the tungsten filament in each bulb is 0.011 m_ The radius of the filament is Se-6 m (it is very thinl). The electron mobility of tungsten is 1.8e-3 (m/s)/(VIm). Tungsten has 6e+28 mobile electrons per cubic meter: Since there are three unknown quantities, we need three equations relating these quantities_ Use any two valid energy conservation equations and one valid charge conservation equation to solve for the following electric field magnitudes: What is the magnitude of the electric field inside bulb #1? 157.58 Vlm What is the magnitude of the electric field inside bulb #2? 78.79 Vlm How many electrons per second enter bulb #1? 6.68e17 electrons/s How many electrons per second enter bulb #27 3.34e17 electrons/s


Answers

A typical small flashlight contains two batteries, each having an emf of 1.5 V, connected in series with a bulb having resistance $17 \Omega$. (a) If the internal resistance of the batteries is negligible, what power is delivered to the bulb? (b) If the batteries last for 5.0 h, what is the total energy delivered to the bulb? (c) The resistance of real batteries increases as they run down. If the initial internal resistance is negligible, what is the combined internal resistance of both batteries when the power to the bulb has decreased to half its initial value? (Assume that the resistance of the bulb is constant. Actually, it will change somewhat when the current through the filament changes, because this changes the temperature of the filament and hence the resistivity of the filament wire.)

.

Enough off. Single battery is 1.5 world, as we have used to Betty's in the finish line Balls. So totally muff will be called tau three point their world presents off. Light bulb is 17 home. And in the first part off this problem, we want to go great power delivered by the libel.

So by using the relation that p equal to so get off re upon, huh? Here we have Walter sequel to three points in the world. A bone. Really? Since off both ways, 79. So we help our delivered by the wolf equal to 0530 What? No. In the second part we have, we have.

There's no biggie less last four or five hours. So here we have time equal to five bars, which is equal to five month supply. 36 double zero to go. Now we want to complete total energy and delivered to the bulls by the benches. So here we have energy.

Is it true power? Times time. Your power delivered by the ball is 0.530 What in through time is five times 36 Double the dose again. So the hell and aren't equal to mine. Fire four zero Do you now in the sea part in a part Because you're our liberties. We're rich.

Nobody says no. Any Donnelly presents there is a sense of real Betty's in grease. Is there a window? So here we hell neglect initial resistance. But when the Bettys random then did a significant effect off and you share significant effect off internal distance off the Bettys in the circuit. So here we hell, given that when the baby's run dome for some time then the power delivered to the world degrees to Hopper's initial value.

So we have new power deliver in above equal toe. Half of the venue calculated in party of this problem which waas zero by 530 What upon too. So the new power believer through the wolf is equal to zero point through six five. What? No. We want to calculate the current flowing through the walls by using the dilation p equal to ice.

A care times are are We can write it. Yes, I equal to scare it off p A bomb. Are nobody putting? Well, you are pee on Well, you off all in the solution. So here I equal to here We helped be equal to zero point to 65 word upon presents off my boat with sir, do you know? So the hooker flames both in this case equal to unified 105 ampere. No way was in the coalition.

You move. Is it cultural? Our times our bullets. I don't capital r hear Tomonaga is the Internet is since off the battery and our capital on is the resistance of the world. No, by putting different Will you see her here? We helped him. Ethical toe three world turn in the circuit equal to zero part 1 to 5 in Pierre Indo are bliss that is since upper liable Who's 17 on? So we have three walked upon.

You don't find one through five and beer is equal to small R plus 17 0 So we have do it before Oh, musical toe are plus or dino our recon right he says are equal to 24 on minus certainly no riches. Ical tool seven home. So this is that intermarry since oh board the budgies.

Hi there. So for this problem we have an in condensing light bulb that uses a coil of filament of to stand and we know that it has a length of 500 and 80 millimeters. Yeah. And we can write this in m zero 58 m now. Yeah, it has a diameter.

We also have that this has a diameter of 46 micro meters. When the temperature tour is gonna say to temperate tour Is of 20 C° And has a racist activity. We also have the resistive itty for the tips 10 and it is 5.25 times 10 to the minus aid arms parameter. Now this tell us that the temperature coefficient of racist activity, it's zero 0.0 0 45 Cells use degrees to the -1 and this remains. Okay.

So we are also told that the temperature of the filament increases linearly with current from 20 degrees two from 20° to 2000 520 associates degrees odd An occurring of one emperor. Okay, so the first question is the question A for this problem is What is the resistance of the light bulb at 20 Celsius degrees? When the temperature is 20 Celsius degrees? Yeah. So the first thing to identify is that this problem is about resistance of a light bulb filament and it can barriers with imperador. We know that the expression for the resistance at a given value of temperature is given by the project between the it's resistive. Itty times its length over the area.

It's gross exceptional area. So in this case we know the value for the resistive itty when The temperature is of 20 social degrees. Is this in here? So we just need to simply substitute that value. We also know the length of it which is 0.58 m. And we also can obtain the area because it will be the area for for um Yeah.

Mhm. For a slender in this case or um So we put all of those, all of those bodies in here. So there is a festivity has a value of 5.25 times. Then To the -8 arms per meter. The length of faith as a size set zero 58 meters.

And this over the area which is hi over the area of the car exceptional area of this filament. So we are given the um yeah, this in here is the diameter. So we obtain the radios of it. So we need to divide that value by two. So we will have And 46 times 10 to the -6.

Does me grow over to this to the square. So when we plot this into the calculator, we obtain that. The resistance has a value of 18.3 arms. So that's the racist activity of the filament when the temperature is of 20 soldiers degrees. Now, for part B of this problem, We are asked what is the current through the light bill? When the potential when the potential difference across east terminal is 120 bolts.

So party of this pope Party of this problem is when the difference, the potential difference is 120 bowls. So what we need to obtain is the current. When we have that value of the potential difference. So we need first to find the temperature or as a function of the current. We know that the graph of temperature versus The current is a straight line passing through zero at 20 Celsius degrees and one impair uh The value of this given volume here, 2000 and 520 social degrees.

So we can obtain the slope from that. And so this lobe is going to be 2500 C° per emperor. And there is a T inter step 20 Phil Hughes degrees. So using the slope intercept equation of a straight line, the equation for dad, the temperature or information of the current is going to be of the following. It's going to be That value 2500 C° and pair.

So with this multiplied by the current because we want that in function of the current And this plus 20 C degrees. Now we know that initial value. When we plot in here, the current equal to zero. We're going to attain 20C degrees. So we can obtain the resistance as a function of temperature.

Or so. The the formula for that is that the resistance in terms of the temperature or is given by the resistance are 20 Celsius degrees times one plus all from t minus the initial 20 Celsius degrees. This constant in here, we are given that value from the beginning. We know that the that this value is this zero point 0045. So we need to blow that value in there and we need to upload the value for the resistance at 20 and social degrees that we just obtained in the part a of this problem.

So we will have that the resistance at this temperature your is going to be so you know, So what what are recording to do now is to combine these two equations to combine these two equations, we plot the temperature in here. So what we are going to obtain is the following that the resistance in function now of the current because we are introducing one into the order is going to be this one plus alpha times um, that expression for that imperator, This is this times the current plus 20 C degrees. Now we note that the bolted or the potential difference is defined as the product between the resistance times the current. So that's what we are going to do. In this case we are plugging the value for the voltage and we are going to solve for the the current.

I so we will have the following will have this volume four. The potential difference, we have the value for There is a festivity at 20 C°. We have one plus we introduce all of the values that we know. 0.0 0 45. Um, seals use degrees over emperors.

There's times 2500 times the other. The current. We need to keep going with the other expression. So it will be 20 Celsius degrees. We close this in here and this in hot and this all of this is going to be times the current eyes.

So when we solve for I, we need to do some algebra in here and we we solve for the current. I we are going to obtain That the positive solution for this quadratic equation. We're going to attain a quadratic equation and the solutions are going to end. The solution for the quadratic equation is going to give us two values, one negative and one positive. Of course we need to take the positive solution and that positive solution is going to be 716 million pairs.

Um, so that's the value for the current. No. Um, the final question. Um, yes parsi of this problem. Yes.

What is the resistance when the potential is 120 bowls? Well this is parsi so. Oh no that's the one I just obtained. Oh no no no this is another when the potential is. Okay so that's part C. Of this problem.

So we want the resistive Itty. Okay the resistance. Sorry when the voltage is again 120 bolts and we just simply need we know that the resistance is the potential difference over the current. So we know these two values because the current is the one that we calculate in part B of this problem. So we just block that in there.

120 bowls over 716 million pairs. We know that million pairs is yeah it can be reading it, it can be reading us 700 sixteen's times 10 to the minus tree on purse. So when we plot this into the calculator, we obtain a value for the resistance of 167 arms. So that's the resistance. When we have that value for the potential um difference.

Now for part D. Of this problem, we are asked how much energy does the light bulb dissipate in one minute When 120 bolts is supplied across it's terminals. So again for this problem we have a potential difference of 120 bowls. But in this case It is applied in one minute. We know that one minute is 60 seconds.

Okay, so we want the energy dissipated during this one minute. So we used the following formula that the energy is equal to the power supplies times the time in that that is applied. So it it also is equal to um because the power can be expressed in terms of the current and the resistance. So it is the power can experience us. The current is four times the resistance and time is the time in this case.

So we are going to use our results from party and see that we just have obtained for the current. And we just need to just substitute those values in here. So we're going to obtain that. The energy is able to the current which is UB 716 million pairs. That is time during the -3 and purse is where the resistance of this um Of this filament of Houston is 167.

Well arms and the time apply is 60 seconds because that's one minute. So the energy that we obtain from this is going to be five point 14 kilo jewels. Now part E of this problem, ask how much energy does the light bulb dissipate in one minute when half of the talk of that voltage is supply. So we're now we have half of that voltage So we will have the report and then voltages 60 falters. If I'm correct.

Yes. And In this case again, the time is 60 seconds. So we want the energy when that we have that value for the potential difference. So we use that. The power in this case the power can also have the following expression.

Power is the product between the current times the potential difference. And we know all of these values. We get the current from the method that we obtain in part B With sits with 60 boulders. So in here We just substitute this by 60 bolt it. So when we solved that, we're going to obtain that, the current is going to be 0.40 nine 49 355 and purse mhm.

And the value of the value of the resistance. And we can obtain just by, oh, there is no space in here. So I'm gonna move this upward so we know that the resistance is going to be um the voltage over the current. So we know these policies. It's the boat over the current that we just have obtained.

So we attended the resistive itty, the resistance or the resistance is equal to 121.6 Emperors. So to obtain the energy, remember that it is the square of the at current times their resistance times the time of life. We know all of these values. We know that the The current 0.49, that value under from purse times these square times the resistance which is dispelled you. And the time that is 60 seconds.

So we obtained finally that the energy in this case is 1.78 kg jews. So that's it for this problem. Thank you..

So in this problem you'll find the power lower four cities, Mr for power do it for cities. As you know that in Siris are regulate is equal to are one Pless are toothless archery It is ironical to our and our physical To her and our physical toe are because all have same Christians. So we get argument in syriza Kowtow three are Yes. You know that Fowler the series will be called to He escaped but by argument when we have to the values we get power in Syria is equal to enough square divide by three are which is the answer off First part of the question No. In the second part, I believe we will find power in parallel for that.

First of all, we'll find excellence for instance, which is called argument is going to one of our urban plus one hour to plus one of our our three is other instances there. Same So we can just do it one hour less when were are that's one or are When we take the same, we get had one or a regular physical 23 Do it by our And when we take reciprocal we get our regulate physical toe. Are you advice? Three. Now we will secure this in the formula off power for president. Physical toe, Enough square dreaded by argument.

Well, it's a shoot. The value. Yeah, our in parallel is equal to three into you have squared, divided by air, which is the strategy. Second part of the question and the third part of the question. The answer is the bulbs will be British internal connection because it is scared from the formula.

Teach power in peril is greater. So this is the answer of her part of the question that develops built..

Hi in a given problem, there are three bulbs in a circuit. These are the two bulbs and the third belt is here like this and two sources of voltage. This is we a Having a value of 6.00 world. The resistance of this bulk Is our one is equal to 10. Home resistance of this bulb are too Is equal to 40 home.

And here This one is our three Is equal to 10 home. Then another battery providing the voltage. VB is equal to 12.0 Volt. No, the terminals here are E. B.

See D. E. And the current coming out of the battery providing the potential way is I WON. And that coming out of another battery is I. To these two currents are joined at this terminal B Giving a current I.

Three. So first of all, using kill jobs junction rule at the junction B. We conclude I one plus I to Is equal to I three. And this is the question # one. No.

In order to find the values of all these three currents. Using your jobs loop rule in the closed loop A. B E F. A. And this creates jobs do proof, says the algebraic sum of all the potential drops.

This is tough. One potential drop taking place across this fastball and that is in clockwise direction, so it will be taken as positive here. This is another potential drop. This is also positive and I'll just break. Some of these two potential drops will be equal to E.

M. F. And the CMF philosophy taken as positive as it is sending the quarantine clockwise direction. So the equation becomes, I even are one plus I. Three.

R. Three. It's equal to be A. Or we can say then I won plus dan the resistance of the artery that is also to know into a tree and in place of I. three.

This is I one plus I took using a question number one is able to V. A. Which is six fold. So finally the situation Comes out to be 20 Ivan less than I do Is equal to six or simply fine by two. This equation takes a form then Ivan.

Yes. Five I two Is equal to three. Finally this is situation number two. No. Using the same jobs luke rule in the clothes globe, B C D E B.

Now here if you look at the circuit again, voltage means the potential drops here. This is the potential rob to into our two that is counter clockwise. Sorry, be taken as negative and I three. R. Three for this look will be counterclockwise.

So here it will be taken as negative and the battery will be sending its quarantine counter clockwise direction. So it will also be taken as a negative. So The question becomes -1 do into our two -1 3. Into our three Is equal to -10. BB.

Taking this negative sign is a common out and plugging in all of the values. This is 40 I-2 plus for rightly this is I one plus I to into 10 Is equal to -12. World canceling this negative sign. Finally, the situation takes a form five Ivan Plus 25 i two Is equal to six. This is a question # three.

No multiplying this equation number two By five. In both sides it becomes 50 are even plus 25 i two is equal to 15. Now subtracting these two equations minus minus minus canceling this I two, we get minus 45. 51 is equal to -9. So finally the value of this island comes out to be nine x 45, canceling this negative sign.

Hence I want He is equal to one x 5 means this is 0.2 M. Pierre one of the answer of this problem. Then putting this value of Ivan Any question #2 We get 10. Ivan means standing to 0.2 plus five two is equal to three. And solving this.

The value of I two here comes out to be 0.2. M. P. R. This one also Another answer for this given problem.

And finally the value of I. three. The current passing through the third bulb using equation number one. I three will be given by I one plus I. To means it becomes zero point for ampere 3rd answer for the third current Passing through the 3rd.

Built now we have to find the power is delivered by the sources of voltage. Also, so for p the power delivered by the first battery using Win too I It will become V. A. Into Ivan as current Ivan is coming out of this battery. So it becomes a 16-0 two Doans this is 1.20.

What? And the power delivered by another battery. We be into I. two. It will be means 12 into 0.2. So it comes out to be 2.40.

What? So these are another two. Answers for the same problem. Thank you..

Similar Solved Questions

1 answer
2. The compound shown below contains a chirality center at nitrogen. Why can't individual stereoisomers of...
2. The compound shown below contains a chirality center at nitrogen. Why can't individual stereoisomers of this compound be isolated at room temperature? (3 points) -CH, н,с 'N H...
5 answers
An object is placed on the principal axis of a convex mirror of focal length $15 mathrm{~cm}$. If the distance of the object from the mirror is $30 mathrm{~cm}$, where should a plane mirror be placed such that the images produced by the two mirrors coincide?
An object is placed on the principal axis of a convex mirror of focal length $15 mathrm{~cm}$. If the distance of the object from the mirror is $30 mathrm{~cm}$, where should a plane mirror be placed such that the images produced by the two mirrors coincide?...
5 answers
Chapto? 5, Scatlon 5.4, Quectlon 03Delenine the gencral solution of the given differential equation that is valid in any interval not including the singular point: xy" 19xy' I00y = 0U2C, C C, for the constants of integration. Enter In |alas In (lal)Equation EditorCommonMatrixsin(e) seclu)cos(a)tin(a)esc(ucotlulfrdt frdr~ia)LUStan()
chapto? 5, Scatlon 5.4, Quectlon 03 Delenine the gencral solution of the given differential equation that is valid in any interval not including the singular point: xy" 19xy' I00y = 0 U2C, C C, for the constants of integration. Enter In |alas In (lal) Equation Editor Common Matrix sin(e) s...
5 answers
And U (nim OO m=0 Ak
and U (nim OO m=0 Ak...
5 answers
CnFind the interval of convergence for the power series: 3nn n=
cn Find the interval of convergence for the power series: 3nn n=...
1 answer
Two wires made of copper and aluminum have the same length and diameter.   The wires are...
Two wires made of copper and aluminum have the same length and diameter.   The wires are fused together end-to-end to form a single wire. A potential difference is applied to the ends of the wire by a battery so that current flows along the wire. What is the ratio of the electron drift vel...
1 answer
DP [20pt] 7. Suppose that the certain population obeys the logistics equation = 0.025 - P....
dP [20pt] 7. Suppose that the certain population obeys the logistics equation = 0.025 - P. (1 - dt where C is the carrying capacity. If the initial population Po= C/3, find the time t* at which the initial population has doubled, i.e., find time tº such that P(t) = 2P = 2C/3....
1 answer
Collins Corporation purchased office equipment at the beginning of 2016 and capitalized a cost of $1,902,000....
Collins Corporation purchased office equipment at the beginning of 2016 and capitalized a cost of $1,902,000. This cost figure included the following expenditures: Purchase price Freight charges Installation charges Annual maintenance charge Total $1,760,000 21,000 11,000 110,000 $1,902,000 The comp...
5 answers
Evaluatee" dx by using trapezoidal rule, taking n = 4, correct to four decimalplaces1.49071.31031.21231.4637
Evaluate e" dx by using trapezoidal rule, taking n = 4, correct to four decimal places 1.4907 1.3103 1.2123 1.4637...
1 answer
Huckvale Corporation manufactures custom cabinets for kitchens. It uses a normal costing system with two direct...
Huckvale Corporation manufactures custom cabinets for kitchens. It uses a normal costing system with two direct cost categories direct materials and direct manufacturing laborand one Indirect cost pool, manufacturing overhead costs. It provides the following information about manufacturing overhead ...
5 answers
One of the earliest embryophyte plants to colonize land (in the Ordovician Period); with non-vascular sporophyte stems; but no leaves or roots_ was the bryophyte group known as: A the horworts (Anthoceratopsida) B. the horsetails (Sphenopsida) Cthe tree ferns (Progymnosperms) D. the true ferns (Filicopsida) E: the seed ferns (Pteridosperms)
One of the earliest embryophyte plants to colonize land (in the Ordovician Period); with non-vascular sporophyte stems; but no leaves or roots_ was the bryophyte group known as: A the horworts (Anthoceratopsida) B. the horsetails (Sphenopsida) Cthe tree ferns (Progymnosperms) D. the true ferns (Fili...
1 answer
An increase in the value of the dollar will lead to a. an increase in aggregate...
An increase in the value of the dollar will lead to a. an increase in aggregate supply as foreign input prices fall. b. a decrease in aggregate demand as net exports decline. c. an increase in real GDP. d. a decrease in real GDP. e. All of the above are theoretically possibl...
1 answer
1) Use the national income identity (S-1) = (G + TR - TA) + (X-M) to...
1) Use the national income identity (S-1) = (G + TR - TA) + (X-M) to answer the following questions as true, false or uncertain and justify your answer. a). If the budget deficit is positive, imports are likely to increase more than exports. (8 points) b) If the budget deficit decreased by $15 billi...
5 answers
L iiu j 1 [ }[ F [ 1 E 1 } L 5 I 1 0 } 1 1 2 } f}{
L iiu j 1 [ } [ F [ 1 E 1 } L 5 I 1 0 } 1 1 2 } f } {...
1 answer
An engineer uses a river (minimum temperature of 4°C) to cool his electrical plant, which heats...
An engineer uses a river (minimum temperature of 4°C) to cool his electrical plant, which heats water with a boiler operating at 220°C. His boiler uses 420 kW of energy to heat water to steam. What is the maximum power output under ideal circumstances? Multiple Choice 416 kW 330 kW 230...
5 answers
Find the arc lengtn of the curve y = In (secx), 0sxs=
Find the arc lengtn of the curve y = In (secx), 0sxs=...
5 answers
Reviow Constunls PeriodicPart Bchloro 3 mothykcyclohexaneDraw the molecule on the canvas by choosing buttons from the Tools (for bonds), Atoms, and Advanced Template toolbars The single bond is active by delaultH: peu Cont0Marvin JS ChemAxonSubmltProvlaus Answels Request Answe
Reviow Constunls Periodic Part B chloro 3 mothykcyclohexane Draw the molecule on the canvas by choosing buttons from the Tools (for bonds), Atoms, and Advanced Template toolbars The single bond is active by delault H: peu Cont 0 Marvin JS ChemAxon Submlt Provlaus Answels Request Answe...
1 answer
РС H2SO4, H20 1. SOC2, EtgN ОН 2. NaOAc I I יא HBr но 0 °C...
РС H2SO4, H20 1. SOC2, EtgN ОН 2. NaOAc I I יא HBr но 0 °C "CHз H2SO4 heat ОН...
1 answer
Spruce Inc. completed Job No. A20 during 2020. The job cost sheet listed the following: Job...
Spruce Inc. completed Job No. A20 during 2020. The job cost sheet listed the following: Job No. A20 Costs for 5000 units produced: Direct materials $30,000 Direct labor $45,000 Manufacturing overhead applied $20,000 Units sold 2,000 units How much is the cost of the finished goods on hand at the end...
1 answer
5. While the carbonyl stretching frequency for simple aldeydes. Ketones is about 1710 cm, the carbony...
5. While the carbonyl stretching frequency for simple aldeydes. Ketones is about 1710 cm, the carbony stretching frequency for esters is about A) 1660 cm B) 1700 cm C) 1735 cm D) 1800 cm E) 2200 cm-1 6. The 'H NMR spectrum of an unknown acid has the following peaks: (ppm) = 12.71 (1H, s). 8.04 (...
1 answer
Selective Estrogen Receptor modulators (SERMS) have two applications. Describe the applications and types of compounds (Agonist/antagonist)...
Selective Estrogen Receptor modulators (SERMS) have two applications. Describe the applications and types of compounds (Agonist/antagonist) used for each application. Application 1: Application 2: How is this situation similar to the clinical situation for beta-receptors?...
5 answers
Page0f3ZomM Ux ertriesTable 5.2-[ find f (t) . where 10s +3 F() 2+45 + 29Table 6 2-1 Leplese Trenetonn Pelr 701t2 0 F6s) #t), nit impulsa at t =0,(t),urit step4 5+0 5+716 + D)(s+ c) (+46 BK6 + €) 2b1e**1#c - 0bIla - 66-77#Jc -0bila -NinarcosorFacintotCos bl7+2en+4DsinanVh-71 V1-0 eco"sin(#V-71+a) V1-? ' ouien;]167(61 + 2r05+ 04)OnntinFnt'TIteWtAMal forced TccnonerThc Modc 0 =f()p"6-aes
Page 0f3 Zom M Ux ertries Table 5.2-[ find f (t) . where 10s +3 F() 2+45 + 29 Table 6 2-1 Leplese Trenetonn Pelr 701t2 0 F6s) #t), nit impulsa at t = 0,(t),urit step 4 5+0 5+716 + D)(s+ c) (+46 BK6 + €) 2 b1e**1 #c - 0 bIla - 6 6-77 #Jc -0 bila - Ninar cosor Facintot Cos bl 7+2en+4 DsinanVh-71...
4 answers
In a cross-sectional data set of the linear model, we expect thevariance of u1 and variance of u2 to be:A. a (regular) random variable.B. identical.C. different.D. none of the above.
In a cross-sectional data set of the linear model, we expect the variance of u1 and variance of u2 to be: A. a (regular) random variable. B. identical. C. different. D. none of the above....
1 answer
Select the major product of the following reaction scheme: Select the major product of the following...
Select the major product of the following reaction scheme: Select the major product of the following reaction scheme: Reaction NaOH H H3C Acetone, EtOH 25 °C А D CH3 CH3 H3C H3C B E ОН О CH3 H3C H3C CH3 C F H H3C (No Reaction) CI ol. A o II. B o III.C o IV.D OV. E...
2 answers
How many moles of hydrogen are in a #3.2*mol# quantity of #"ammonium hydroxide"#?
How many moles of hydrogen are in a #3.2*mol# quantity of #"ammonium hydroxide"#?...
1 answer
PRE-LAB QUESTIONS 1. What is the term given to two electrons shared by two atoms? 2....
PRE-LAB QUESTIONS 1. What is the term given to two electrons shared by two atoms? 2. An even symmetrical arrangement of atoms and electron density in a molecule gives a _ molecule. 3. Define: a. octet rule b. hybridization c. electron-pair geometry d. molecular geometry 4. What two criteria must be ...
1 answer
I REALLY need numbers 2 and 3 and 5 by like tomorrow morning. I have no...
I REALLY need numbers 2 and 3 and 5 by like tomorrow morning. I have no clue how to do these. I know the image quality is iffy but please help as best you can Homework1 STA4322 Homework 1, Spring 2019 Please turn in your own work, though you may discuss the problems with classmates, the TA, the P...
1 answer
Present and future value tables of $1 at 3% are presented below: N FV $1 PV...
Present and future value tables of $1 at 3% are presented below: N FV $1 PV $1 FVA $1 PVA $1 FVAD $1 PVAD $1 1 1.03000 0.97087 1.0000 0.97087 1.0300 1.00000 2 1.06090 0.94260 2.0300 1.91347 2.0909 1.97087 3 1.09273 0.91514 3.0909 2.82861 3.1836 2.91347 4 1.12551 0.88849 4.1836 3.71710 4.3...
1 answer
This Question: 1 pt 8 of 10 (3 complete) This Test: 10 pts possibl The Rise...
This Question: 1 pt 8 of 10 (3 complete) This Test: 10 pts possibl The Rise of Ambient Music Erik Satie's idea of creating new works designed to function specifically as ambient music caught the imagination of a number of talented composers in the last quarter of the 20 century. This kind of amb...
5 answers
Vraag Question 1 Wat beteken die volgende? / What is the meaning of the following? 1.1_ 'n Haploide genoom A haploid genome 1.2. Heterochromatien Heterochromatin 1.3. Enkelkopie-geen A single-copy gene 1.4. Tandemherhalende DNA Tandemly repetitive DNA 1.5. Nie-koderende genomiese DNA Non-coding genomic DNA(5x2-10)
Vraag Question 1 Wat beteken die volgende? / What is the meaning of the following? 1.1_ 'n Haploide genoom A haploid genome 1.2. Heterochromatien Heterochromatin 1.3. Enkelkopie-geen A single-copy gene 1.4. Tandemherhalende DNA Tandemly repetitive DNA 1.5. Nie-koderende genomiese DNA Non-coding...
5 answers
Tav () + taukJ Z 1=0
tav () + taukJ Z 1=0...
1 answer
How many even positive integers are less than 42
How many even positive integers are less than 42?...

-- 0.024139--