5 answers

A bag contains 9 red marbles, 5 white marbles, and 6 blue marbles. You draw 4 marbles out at random,

Question:

A bag contains 9 red marbles, 5 white marbles, and 6 blue marbles. You draw 4 marbles out at random, without replacement. What is the probability that all the marbles are red?


Answers

A bag contains 9 red marbles, 5 white marbles, and 6 blue marbles. You draw 4 marbles out at random, without replacement. What is the probability that all the marbles are red?

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In this problem. I'm choosing marbles out of the bag, and I know I want to find the probability of picking a blue marble, not putting it back. Then picking a green mark you can see have drawn the marble situation out there. Three red four green to yellow, which I don't have yellow marker. So it's black and five blue.

The first thing I'm going to do is total. The number of marbles three plus four is seven plus two is nine plus five is 14. So the first denominator will be 14 because that's the total number of marbles. Next since my first pick, I want to be blue. I see how Maney blue marbles there are, which is five.

Now let's assume I have picked one of those marbles, so I'm going to erase one from the bag because I've taken it out and I didn't put it back. That now changes the total number of marbles in my bag. So for my second fraction, the denominator is no longer 14. It drops down 13 since I took one marble out. Now I want my second marble to be green, so I see how many green there are, which is for so I put a four in the numerator.

Finally to finish, I multiply story across the numerator straight across the nominator. Five times four is 20 and 14 times 13 is 182. So I have now found the probability of picking a blue marble, not replacing it..

Hello students in this question we have a jar that contains for red marbles. Who white marbles and four Blue Marbles. OK blue marbles. Now we have to choose the two marbles randomly randomly. Big replacement with replacement.

Okay now we have to determine the probability the probability for choosing. Yeah read and then blue. Okay now we can see here that the total number of marbles capital and is equal to four plus two plus four. So this comes out to be 10. Okay now we have four red marbles.

So the probability for red probability For rare will be given by four divided by total number. That is 10. Okay now we have replaced another ball so that total balls become against 10. So now we can say here that the probability for blue will be given by the blue balls are four so four and the total balls here are 10. So we can say here that total probability total probability really it was too four by 10.

Molecular B four by 10. Okay. Or it can be written here as for the verb. 25. Okay, so this is the answer of this problem here.

Okay thank you.

In this problem. I know. I'm trying to find the probability of picking a blue marble, not replacing it been a yellow marble and not replacing it. And then a red marble. I've drawn out the marble situation.

You can see there are three red marbles or green to yellow, which I had to draw in black because I don't of yellow marker and five blue. The first thing I'm going to do is figure out the probability of picking a blue marble. I first start by totaling up the number of marbles. There are 14 marbles in total. Next I ask myself, how many of those 14 marbles are blue, which the answer is five.

Now I'm going to assume that I've taken one of those five blue marbles out of the back. This means that there's no longer 14 marbles in the back. I've taken one out, so there's only 13 marbles. So my new denominator is 13. Now I see of those 13 how maney or yellow? Remember my black represents yellow.

There are two. Let's now assume I take one of those out. This now means there are no longer 13 marbles in my bag. We have now dropped 12 marbles. And now I ask myself of those 12 how many are red? And the answer is three.

To finish this, I'm going to multiply my fractions together. And to do that I multiply straight across the numerator and straight across the denominator. Five times, two times three is 30 and 14 times 13 times 12 is 2000 184. So that is our probability of picking a blue, a yellow and then a red without replacing any of the marbles 30 over..

In this question. I know I'm trying to find the probability off picking three green marbles in a row without replacing them. The first thing I'm going to do is figure out how many marbles I have in total. As you can see, I have drawn out the marble situation. There are three red marbles, four green marbles to yellow marbles, which I had to draw on black, since I don't have a yellow and five blue when I add all of the's up.

Three plus for a seven plus two is nine plus five makes 14 total marbles, so starting with the first green, it's denominator would be a 14 since there are 14 marbles total. Next, I see how many green marbles there are, which is for now. Let's assume we took one of those green marbles out This. Now adjust the total number of marbles in our back. There's no longer 14.

I've taken one out, so we only have 13 in the back. Also, there are no longer four green marbles. I've taken one out, so there's only three left. Now. I will show taking that marble out by erasing it.

And now, for the third green marble. We no longer have 13 marbles in the bag we've now taken to out. So we're down to 12 total marbles and there are no longer three green marbles. There's only two. Now I am going to go ahead and multiply my probabilities together to find my final answer.

Four times three is 12 times two. Makes 24 in the numerator. Note. When you multiply fractions, you multiply straight across the numerator and straight across the denominator. 14 times, 13 times 12 is 2000 184.

So that is the probability of picking three green marbles in a row without replacing them 24..

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