1 answer

How to do 40 In Problems 39-42, multiply both sides of the equation by the LCD...

Question:

How to do 40
In Problems 39-42, multiply both sides of the equation by the LCD and solve the resulting quadratic equation. 39. x 15 w xwgi
In Problems 39-42, multiply both sides of the equation by the LCD and solve the resulting quadratic equation. 39. x 15 w xwgisla 3d x - 2 x + 1 129

Answers

LCD is a special case of LCM .

to find LCD find LCM of denominators in fraction.

here given expression is

3 - 1 = - 2

here denominator are (x-2) and (x+1)

To find LCD find Lcm of (x-2) and (x+1)

We have no common multiple for x-2 and x+1 .so to get Lcm multiply both.

so LCM LCD is (x-2)(x+1)

now multiply LCD on both side

3 -(x 2)(x1) x2)(1) 1 2

( 2) (x1) 1 2) (x) -1 (r -2) (x1) 2

now cancel common terms in numerator and denominator of different parts of equation

(x 1)- (-2) ( 1)3(TI2)

take (x+1) as common in left side

1)(- 2) 3(x - 2)

21 2(r1)3(r

now open brackets

2x+ 2 = 3x-6

3x-2x= 2+6

x= 8

so solution is x=8

.

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